A body of mass 2kg falls from rest what will be its k.e. during the fall at the end 2 seconds .

A body of mass 2kg falls from rest what will be its k.e. during the fa

1.	A body of mass 2kg falls from rest what will be its k.e. during the fall at the end 2 seconds .
Answer» G = 9.8m/s , m = 2 kg t = 2 seconds u = 0 V = ? v = u + gt *= 0 + 9.8 2 = 19.6 m/s K.E.=? $\frac{1}{2} mv^2$ K.E.=** $\frac{1}{2} * 2 (19.6 )^2$ = = 384.16 J*

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A body of mass 2kg falls from rest what will be its k.e. during the fall at the end 2 seconds .

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