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A body of mass `2kg` travels according to the law `x (t) = pt + qt^(2) + rt^(3)` where `p = 3ms^(-1),q = 4 ms^(-2)` and `r = 5ms^(-3)` .A. `136N`B. `134N`C. `158N`D. `68N` |
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Answer» Correct Answer - a Here, `m = 2kg` `x (t) = pt + qt^(2) + rt^(3)` `upsilon = (dx)/(dt) = p + 2 qt + 3rt^(2)` `a = (d upsilon)/(dt) = 0 + 2q + 6rt` As `t =2 sec, a = 2q + 12 r = 2xx4 + 12 xx5 =68m//s^(2)` `F =ma = 2 xx 68 N = 136 N` . |
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