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A body of mass 5 kg is moving with velocity of `v=(2hati+6hatj)ms^(-1)` at t=0s. After time t=2s, velocity of body is `(10 hati+6 hatj)`, then change in momentum to body isA. `40 hati kgms^(-1)`B. `20hati kgms^(-1)`C. `30 hati kgms^(-1)`D. `(50 hati+30 hatj)kgms^(-1)` |
Answer» Correct Answer - A (a) Mass m= 5kg Change in velocity `v_(f)-v_(i)=[(10-2) hati+(6-6) hatj]` Change in momentum `=m Delta v=5[8hati]=40 hati kgms^(-1)` |
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