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A body of mass 6 kg is floating in a liquid with `2//3` of its volume inside the liquid. Find (i) buoyant force acting on the body and (ii) ratio between the density of the body and density of liquid. Take `g=10m//s^(2)`. |
Answer» when a body floats, the buoyant force on the body is equal and opposite to the weight of body. So, Buoyant force = weight of body `= 6 kg xx 10m//s^(2)=60N` Let V be the volume of the body. Buoyant force = wt. of liquid displaced `((2)/(3)V) rho_(l)g` Weight of body `= Vrho_(b) g` when body floating, then `V rho_(b) g = 2/3 V rho_(l) g or (rho_b)/(rho_l) = 2/3`. |
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