1.

A body of mass 6 kg is floating in a liquid with `2//3` of its volume inside the liquid. Find (i) buoyant force acting on the body and (ii) ratio between the density of the body and density of liquid. Take `g=10m//s^(2)`.

Answer» when a body floats, the buoyant force on the body is equal and opposite to the weight of body.
So, Buoyant force = weight of body
`= 6 kg xx 10m//s^(2)=60N`
Let V be the volume of the body.
Buoyant force = wt. of liquid displaced
`((2)/(3)V) rho_(l)g`
Weight of body `= Vrho_(b) g`
when body floating, then
`V rho_(b) g = 2/3 V rho_(l) g or (rho_b)/(rho_l) = 2/3`.


Discussion

No Comment Found

Related InterviewSolutions