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A body of mass `m_(1) ` moving with uniform velocity of 40 m/s collides with another mass `m_(2)` at rest and then the two together begin to moe wit h uniform velocity of 30 m/s. the ratio of their masses `(m_(1))/(m_(2))` isA. `1:3`B. `3:1`C. `1:1.33`D. `1:0.75` |
Answer» Correct Answer - B (b) Initial momentum of the system `m_(1)xx40+m_(2)xx0=40m_(1)` Final momentum of the system=`(m_(1)+m_(2))xx30)` By the law of consevation of momentum, Initial momentum= Final momentum `40m_(1)=(m_(1)+m_(2))30 ` `40 m_(1)-30m_(1)=30m_(2)` `10m_(1)=30m_(2)` `(m_(1))/(m_(2))=3/1` |
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