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A body of mass M at rest explodes into three pieces, two of which of mass M//4 each are thrown off in prependicular directions eith velocities of `3//s` and `4m//s` respectively. The third piece willl be thrown off with a velocity ofA. `1.5 ms^(-1)`B. `2 ms^(-1)`C. `2.5 ms^(-1)`D. `3 ms^(-1)` |
Answer» Correct Answer - C ( c) Momentum of one piece` =(M)/(4)xx3` Momentum of other piece`=(M)/(4)xx4` `therfore` Resultant momentum`=sqrt((9M^(2)/(16)+M^(2))=(5M)/(4)` The third piece should also have the same momentum. Let its velocity be v, then `(5M)/(4)=(M)/(2)xxv impliesv=(5)/(2)=2.5 ms^(-1)` |
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