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A body of mass `m` is dropped and another body of mass `M` is projected vertically up with speed `u` simultaneously from the top of a tower of height `H`. If the body reaches the highest piont before the dropped body reaches the ground, then maximum height raised by the centre of mass of the system from ground isA. `H+(u^(2))/(2g)`B. `(u^(2))/(2g)`C. `H+1/(2g)((Mu)/(m+M))^(2)`D. `H+1/(2g)((m u)/(m+M))^(2)` |
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Answer» Correct Answer - C `h_(max)=H+((u_(cm))^(2))/(2g)` |
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