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A body of mass m moves along X-axis such that its position coordinate at any instant t is ` x = at^(4) - bt^(3) + 2 ct^(2) - (3d)t` where a,b,c,d are constants What is the force acting on the particle at instant ? |
Answer» Correct Answer - `F = m (12at^(2) - 6bt +2c)` Here, `x = at^(4) - bt^(3) + 2 ct^(2) - 3 d (t)` velocity, `upsilon = (dx)/(dt) = 4 at^(3) - 3 bt^(2) + 2 ct - 3 d` Acceleration, `a = (d upsilon)/(dt) = 12 at^(2) - 6 bt + 2 c` Force `F = ma = m(12 at^(2) - 6 bt + 2 c)` . |
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