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A body of mass M moving with velocity V collides head-on with another body of mass 2M lying at rest. Comparethe kinetic energies of the colliding body before and aftercollision.40. |
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Answer» By conservation of linear momentum 2mv' =mvv'=v/2 Hence velocity of body of mass m after collision is ,v1=(m−2m)/(m+2m)u1 =−u1/3 Therefore ,K.E before collision/K.E after collision=(1/2m1u1^2)/(1/2m1v1^2) = 9:1 |
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