InterviewSolution
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InterviewSolution
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A body of mass `m` slides down an smooth incline and reaches the bottom with a velocity, Now smooth incline surface is made rough and the same mass was in the form of a ring which rolls down this incline, the velocity of the ring at the bottom would have been:A. `sqrt(2v)`B. `v`C. `(sqrt(2/5))v`D. `v//sqrt(2)` |
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Answer» Correct Answer - D For a sliding body of mass `m` `v_("body")=sqrt(2gh)=v`………..i For a rolling of same mass `m` `v_("ring")=sqrt((2gh)/g)` `=sqrt((2gh)/(1+I/(mR^(2))))=sqrt((2gh)/(1+(mR^(2))/(mR^(2))))=sqrt((2gh)/2)=sqrt(gh)=v/(sqrt(2))` |
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