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A body rolled on ice with a velocity of `8 ms^(-1)` comes to rest after travelling a distance of 4 m . Calculate the coefficient of friction . |
Answer» Here , ` u = 8 m // s , upsilon = 0 , s = 4 m , a = ? ` From ` v^(2) - u^(2) = 2` as `0 - 8^(2) = 2 (a) 4 = 8 a` ` a = - (64)/(8) = - 8 m// s^(2) ` Negative sigh represents retardation of body ` mu = (f)/(R) = (ma)/(mg) = (a)/(g) = (8)/(9.8) = 0.816` . |
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