A body start it's motion from rest and covered 200m in first 19second

1.	A body start it's motion from rest and covered 200m in first 19second .find acceleration of the motion
Answer» Answer: S=(1/2)at^2+ut (here u=0 because the BODY is INITIALLY at rest) so ,S=(1/2)at^2 now PUTTING the value, 200=(1/2)a(19)^2 400=a(361) a=(400/361) a=1.1080m/sec^2

A body start it's motion from rest and covered 200m in first 19second .find acceleration of the motion

Answer»

Answer:

S=(1/2)at^2+ut

(here u=0 because the BODY is INITIALLY at rest)

so ,S=(1/2)at^2

now PUTTING the value,

200=(1/2)a(19)^2

400=a(361)

a=(400/361)

a=1.1080m/sec^2

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A body start it's motion from rest and covered 200m in first 19second .find acceleration of the motion​

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A body start it's motion from rest and covered 200m in first 19second .find acceleration of the motion