1.

A body starting from rest accelerates at a constant rate a m/s for some time afterwhich it decelerates at a constant rate b m/s to come to rest finally. If the total timeelapsed is t sec, the maximum velocity attained by the body is given byab(A) -1 m/s (B) dms(22abm/st mI sa+ba- ba+ ba-b

Answer»

Assume that to plot a graph of velocity and speedAccelerating rate is v/aDeccelerating rate is v/bTimd for acceleration t1and decceleration t2total time t sec is =t1+t2Time=velcity/rate(acc+decc)Here u need to find max velocity so,v/a+v/b=t1+t2v/a+v/b=tv=ab/a+b*t m/s



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