InterviewSolution
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InterviewSolution
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A body starts from rest from the origin with anacceleration of 6m/s2 along the x-axis and8m/s2 along the y-axis. Its distance from theorigin after 4 seconds will be:(1) 56 m(3) 80 m95.(2) 64 m(4) 128 mThe x and y coordinates of a particle at any timet are given by x 7t + 4t2 and y 5t, where x96.and y are in metre and t in seconds. Theacceleration of particle at t 5 s is:(1) Zero(3) 20 m/s2(2) 8 m/s2(4) 40 m/s2 |
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Answer» Using Newton's second formula of motion Sx = 1/2*ax*t² = 1/2*6*4² = 48m and Sy = 1/2*ay*t² = 1/2*8*4² = 64m so, distance from origin is = √48²+64² = 80m option 3. acceleration in x direction = d²x/dt² = d(7+8t)/dx = 8m/s² acceleration in y direction = d²y/dt² = d(5)/dt = 0 so only acceleration is 8m/s². option 2 Can u answer it using projectile motion. answer will be same im any case... for projectile eliminate t from both the equation.. and write equation of y in terms of x. |
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