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A body takes time `t` to reach the bottom oa a smooth inclined plane of angle `theta` with the horizontal. If the plane is made rought, time taken now is `2t`.The coefficient of friction of the rough surface isA. `(3)/(4) tan theta`B. `(2)/(3) tan theta`C. `(1)/(4) tan theta`D. `(1)/(2) tan theta` |
Answer» Correct Answer - A `S = (1)/(2) at^(2)` `:. t= sqrt((2S)/(a)` or `t prop (1)/(sqrt(a))` `:. (t_(1))/(t_(2)) = ((a_(2))/(a_(2)))` or `(t)/(2t) = ((g sin theta - mug cos theta)/(g sin theta ))` On solving this equation , we get `mu (3)/(4) tan theta` |
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