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A body thrown vertically upwards with an initial valocity `u` reaches maximum height in 6 s. The ratio of the distances traveled by the body in the first second the seventh second isA. `1:1`B. `11:1`C. `1:2`D. `1:11` |
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Answer» Correct Answer - B Velocity becomes zero after `6 s`. `0=u-gxx6impliesu=60 m//s` Distance in the first second `s_(1)=ut-1/2g t^(2)=60xx1-1/2xx10xx1^(2)=55 m` (i) After `6 s`, particle is moving in downward direction. (ii) Distance in the `7^(th)` second, `s_(2)=(1)/(2).10.1^(2)=5 m` `s_(1)/s_(2)=55/5=11/1` |
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