a body undergoes uniformly accelerated motion. its velocity after 6 se

1.	a body undergoes uniformly accelerated motion. its velocity after 6 seconds is 22m/s after 10 seconds it is 34m/s. Calculate the distance covered in 12th second.
Answer» EXPLANATION: from the given information acceleration is 3 m/s^2 & initial VELOCITY is 4m/s distance covered in NTH second is u + a(n-0.5) s = 4+3×23/2 = 38.5 m

a body undergoes uniformly accelerated motion. its velocity after 6 seconds is 22m/s after 10 seconds it is 34m/s. Calculate the distance covered in 12th second.

Answer»

EXPLANATION:

from the given information acceleration is 3 m/s^2 & initial VELOCITY is 4m/s

distance covered in NTH second is u + a(n-0.5)

s = 4+3×23/2

= 38.5 m

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a body undergoes uniformly accelerated motion. its velocity after 6 seconds is 22m/s after 10 seconds it is 34m/s. Calculate the distance covered in 12th second.

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