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A body weighing 1,000kg accelerates uniformly from 10m/s to 20m/s. Find the amount of work doneduring this period.[(150kl]4. |
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Answer» Kinetic energy=1/2mv2change in velocity means=1/2mv2- 1/2mu2 ( v= final , and u=intial)taking common, we get=1/2m(v2-u2)=1/2*1000(202-102)=500*300=150000J thz |
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