A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of `9m//s` and `12//s` Calculate the speed of the third fragment .

A bomb at rest explodes into three fragments of equal massses Two frag

1.	A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of `9m//s` and `12//s` Calculate the speed of the third fragment .
Answer» Correct Answer - `-15m//s` . Let m be the mass of each fragment `:. P_(1) = mxx 9,p_(2) = m xx 12` As`vec(p_(1))` and` vec(p_(2))` are perpendicular to each other therefore resultant momentum of the two fragments `p = sqrt(p_(1)^(2) + p_(2)^(2)) = sqrt((9m)^(2) +(12m)^(2)) = 15m` According to the principle of conservation of linear momentum `vec(p) + vec(p_(3)) = 0` `vec(p_(3)) = - vec(p) = - 15 m ` `m xx upsilon_(3) = - 15m` `upsilon_(3) = -15m//s` Negative sign implies that third fragment will fly in a direction opposite to the direction of resultant momentum of the two fragments.

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A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of `9m//s` and `12//s` Calculate the speed of the third fragment .

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