A bomb of mass 8 kg at rest explodes in three fragments. Two equal mas

1.	A bomb of mass 8 kg at rest explodes in three fragments. Two equal masses of 2kg each fly off at 20 m/s perpendicular to each other. Find magnitude and direction of velocity of third fragment.
Answer» Answer: 10√2 m/s According to LAW of CONSERVATION of Linear momentum MV = m1v1 + m2V2 + m3v3 V= 0 0 = 40i + 40j + 4v v = -10I -10j \|V\| = 10√2 Thanks for READING

A bomb of mass 8 kg at rest explodes in three fragments. Two equal masses of 2kg each fly off at 20 m/s perpendicular to each other. Find magnitude and direction of velocity of third fragment.

Answer»

Answer:

10√2 m/s

According to LAW of CONSERVATION of Linear momentum

MV = m1v1 + m2V2 + m3v3

V= 0

0 = 40i + 40j + 4v

v = -10I -10j

|V| = 10√2

Thanks for READING

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A bomb of mass 8 kg at rest explodes in three fragments. Two equal masses of 2kg each fly off at 20 m/s perpendicular to each other. Find magnitude and direction of velocity of third fragment.

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