. A bomb of mass 9 kg explodes into two pieces ofmasses 3 kg and 6 kg.

1.	. A bomb of mass 9 kg explodes into two pieces ofmasses 3 kg and 6 kg. The velocity of mass 3 kgis 16joule is(1) 196(3) 192m/s. The kinetic energy of mass 6 kg in0 180(2) 320(4) 620
Answer» mass of the bomb ,M=9kg initial value of the bomb=0m/s mass of smaller fragmet =3kg=m1 (let) velocity of the smaller part just after explosion=16m/s mass of the bigger fragmet =6kg=m2 (let) let, velocity of the bigger part just after explosion= v as there is no external force is acting on the bomb intially so the momentum is conserved in all direction i.e P(just after explosion)=P(just before explosion ) m116 + m2v = M0 => v = -8m/s so the kinetic energy of the fragment of mass 6kg = (1/2)m2vv Joule =(1/2)664 =192 Joule

. A bomb of mass 9 kg explodes into two pieces ofmasses 3 kg and 6 kg. The velocity of mass 3 kgis 16joule is(1) 196(3) 192m/s. The kinetic energy of mass 6 kg in0 180(2) 320(4) 620

Answer»

mass of the bomb ,M=9kg

initial value of the bomb=0m/s

mass of smaller fragmet =3kg=m1 (let)

velocity of the smaller part just after explosion=16m/s

mass of the bigger fragmet =6kg=m2 (let)

let, velocity of the bigger part just after explosion= v

as there is no external force is acting on the bomb intially

so the momentum is conserved in all direction

i.e P(just after explosion)=P(just before explosion )

m1*16 + m2*v = M*0

=> v = -8m/s

so the kinetic energy of the fragment of mass 6kg = (1/2)*m2*v*v Joule

=(1/2)*6*64

=192 Joule

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