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A boy of `30kg` weight sitting on a horse whips it the horse speeds up at an average acceleration of `2 m//s^(2)` (a) If the boy does not slide back what is the force of friction exerted by the horse on the boy ? (b) If the body slides back during the acceleration what can be said about the coefficient of static friction between the horse and the boy ? Take `g = 10 ms^(2)` . |
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Answer» (a) As the boy does not slide back , its acceleration = acc of the horce `:. f_(s) = M a = 30 (2.0) = 60 N` (b) If the boy slides back the horse could not nexert a friction of `60` N on the boy Maximum force of static friction `f_(s) = mu_(s) R= mu_(s) (M g) :. mu_(s) (30) (10) le 60 N` `:.` Max value of coeff of static friction `= mu_(s) = (60)/(300) = 0.20` . |
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