1.

A boy stands on a weighing machine inside a lift.When the lift is going down with acceleration g/4, themachine shows a reading 30 kg. When the lift goesupwards with acceleration g/4, the reading would be(1) 18 kg(3) 50 kg10.(2) 37.5 kg(4) 67.5 kg

Answer»

when lift goes downwards then seudo force acts on boy in upward direction...

if a is the accleration of lift then

mg - ma = net weight=30g ...........1 (given) g is accleration due to gravity

m(g-a) = 30g

m=40kg

when lift goes upward then seudo force acts in downward direction so now net weight

mg + ma = W

40(a+g) = W

50kg = W



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