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A boy throws n balls per second at regular time intervals. When the first ball reaches the maximum height he throws the second one vertically up. The maximum height reached by each bass isA. `(g)/(2(n-1)^(2))`B. `(g)/(2n^(2))`C. `(g)/(n^(2))`D. `(g)/(n)` |
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Answer» Correct Answer - B Time interval between two balls`=` Time of ascend `=(1)/(n)=(u)/(g)u=(g)/(n),h=(u^(2))/(2g)` |
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