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A brake applied to a train moving at 90 km/hr produces the retardation of 5m/s².What distance will it cover before coming to a stop. |
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Answer» Answer: The train will cover 62.5m before it comes to a stop Explanation: Using the equation v^2 = U^2 + 2as we can say u(INITIAL velocity) = 90kmph = 25 m/s and final velocity v is 0 since the train comes to a stop Acceleration = -5m/s (retardation) Plugging the VALUES in, we get 0^2 = 25^2 + 2(-5)(s) -25 x 25 = -10s s = 625/10= 62.5 m
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