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A bucket isin the form of a frustum of a cone and holds 28.490 litres of water. Theradii of the top and bottom are 28 cm and 21 cm respectively. Find the heightof the bucket. |
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Answer» Given volume of the frustum = 28.49 L `= 28.49 xx 1000 cm^(3)" "[therefore 1 L = 1000 cm^(3)] ` `= 28490 cm^(3)` and radius of the top `(r_(1) )= 28 cm` radius of the bottom `(r_(2)) = 21 cm` Let height of the bucket = h cm Now, volume of the bucket `= (1)/(3) pi h(r_(1)^(2) + r_(2)^(2) + r_(1)r_(2))= 28490 ` `rArr " " (1)/(3) xx (22)/(7) xx h (28^(2) + 21^(2) + 28xx 21) =28490` `rArr " "h (784 + 441 +588) = (28490xx3xx7)/(22)` `rArr " " 1813 h = 1925 xx 12` `therefore" "h=(1295 xx 21)/(1813) = (27915)/(1813) = 15 cm` |
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