A bulb is rated at 330V-110W. what do you think is its resistence? thr

1.	A bulb is rated at 330V-110W. what do you think is its resistence? three such bulbs burn for 5 hrs at a stretch. what is the energy consumed? calculate the cost in rupees if the rate is 70 paise per unit
Answer» we know that for an electric appliance P = V2/R or resistance will be given as R = V2 / P So, P = 110w V = 330 volts R = 3302 / 110 = 108,900/110 = 990 thus, resistance of the BULB is 990 now, electric energy consumed will be E = number of units x POWER of each unit x time = N x P x t n = 3 P = 110 W t = 5 hours so, E = 3 x 110 × 5 thus, E = 1650Wh .. the total cost of electricity = total unit of energy consumed x cost per unit = 1650 x 0.7 Rs thus, total cost= 1155rs. and monthly cost = total daily cost x number of DAYS in month = 1155rs. × 30 = 34,650rs. hope this will HELP...

A bulb is rated at 330V-110W. what do you think is its resistence? three such bulbs burn for 5 hrs at a stretch. what is the energy consumed? calculate the cost in rupees if the rate is 70 paise per unit

Answer»

we know that for an electric appliance

P = V2/R

or resistance will be given as R = V2 / P

So,

P = 110w

V = 330 volts

R = 3302 / 110

= 108,900/110 = 990

thus, resistance of the BULB is 990

now, electric energy consumed will be

E = number of units x POWER of each unit x time = N x P x t

n = 3

P = 110 W

t = 5 hours

so,

E = 3 x 110 × 5

thus,

E = 1650Wh

the total cost of electricity = total unit of energy consumed x cost per unit

= 1650 x 0.7 Rs

thus,

total cost= 1155rs.

and

monthly cost = total daily cost x number of DAYS in month

1155rs. × 30 = 34,650rs.

hope this will HELP...

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