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A bulet of mass 0.04kg moving with a speed of 90m/s enters aheavy wooden block and is stopped after a distance of 60cmWhat is the average resistive force exerted by the block on bulletE. |
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Answer» v²-u²=2ax0-(90)²=2a0.6thereforea=-1500ms-²now F=mathereforeF=0.04*-1500thereforeF=60N |
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