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A bullet hits a wall with a velocity of 20 m/s andpenetrates it up to a distance of 5 cm. Find thedeceleration of the bullet in the wall. |
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Answer» U= 20 m/sv= 0s = 5 cm = 0.05 m from 3rd equation,v² -u² = 2as⇒0 - (20)² = 2×0.05×a⇒0.1 a = - 400⇒a = - 4000 m/s² deceleration will be - 4000 m/s² |
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