1.

A bullet is moving at a speed of 367 m/swhen it embeds into a lump of moist clayThe bullet penetrates for a distance of0.0621 m. Determine the acceleration ofthe bullet while moving into the clay(Assume a uniform acceleration.)

Answer»

Given:

vi = 367 m/s

vf = 0 m/s

d = 0.0621 m

Find:

a = ??vf2 = vi2 + 2*a*d(0 m/s)2 = (367 m/s)2 + 2*(a)*(0.0621 m)

0 m2/s2 = (134689 m2/s2) + (0.1242 m)*a

-134689 m2/s2 = (0.1242 m)*a

(-134689 m2/s2)/(0.1242 m) = a

a = -1.08*106 m /s2

(The - sign indicates that the bullet slowed down.)



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