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A bullet is moving at a speed of 367 m/swhen it embeds into a lump of moist clayThe bullet penetrates for a distance of0.0621 m. Determine the acceleration ofthe bullet while moving into the clay(Assume a uniform acceleration.) |
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Answer» Given: vi = 367 m/s vf = 0 m/s d = 0.0621 m Find: a = ??vf2 = vi2 + 2*a*d(0 m/s)2 = (367 m/s)2 + 2*(a)*(0.0621 m) 0 m2/s2 = (134689 m2/s2) + (0.1242 m)*a -134689 m2/s2 = (0.1242 m)*a (-134689 m2/s2)/(0.1242 m) = a a = -1.08*106 m /s2 (The - sign indicates that the bullet slowed down.) |
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