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A bullet leaves a rifle with a muzzlevelocity of 521 m/s. While acceleratingthrough the barrel of the rifle, the bulletmoves a distance of 0.840 m. Determinethe acceleration of the bullet (assume auniform acceleration) |
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Answer» Given: vi = 0 m/s vf = 521 m/s d = 0.840 m Find: a = ??vf2 = vi2 + 2*a*d(521 m/s)2 = (0 m/s)2 + 2*(a)*(0.840 m) 271441 m2/s2 = (0 m/s)2 + (1.68 m)*a (271441 m2/s2)/(1.68 m) = a a = 1.62*105 m /s2. |
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