1.

A bullet leaves a rifle with a muzzlevelocity of 521 m/s. While acceleratingthrough the barrel of the rifle, the bulletmoves a distance of 0.840 m. Determinethe acceleration of the bullet (assume auniform acceleration)

Answer»

Given:

vi = 0 m/s

vf = 521 m/s

d = 0.840 m

Find:

a = ??vf2 = vi2 + 2*a*d(521 m/s)2 = (0 m/s)2 + 2*(a)*(0.840 m)

271441 m2/s2 = (0 m/s)2 + (1.68 m)*a

(271441 m2/s2)/(1.68 m) = a

a = 1.62*105 m /s2.



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