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A bullet of mass 10 g moving with a speed of `20 m//s` hits an ice block of mass 990 g kept on a frictionless floor and gets stuck in it. How much ice will melt if `50%` of the lost kinetic energy goes to ice? (Temperature of ice block `= 0^@C`.) |
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Answer» Correct Answer - C Velocity of bullet + ice block, `V = ((10g)xx(20 m//s))/1000 g = 0.2 m//s` Loss of KE `= 1/2 mv^2 - 1/2 (m+M)V^2` `= 1/2 [0.01 xx (20)^2 - 1 xx (0.2)^2]` `=1/2 [4- 0.04] = 1.98 J` `:.` Heat received by ice block `= (1.98)/(4.2 xx2) cal ` `= 0.24 cal` `:.` Mass of ice melted `= (0.24cal)/(80 cal//g)` `=0.003 g` . |
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