A bullet of mass 10g travelling horizontally with a velocity of 150 m/s strikes a stationary wooden block and comes to rest in 0.03 sec. Calculate the distance of penetration of the bullet into the

A bullet of mass 10g travelling horizontally with a velocity of 150 m/

1.	A bullet of mass 10g travelling horizontally with a velocity of 150 m/s strikes a stationary wooden block and comes to rest in 0.03 sec. Calculate the distance of penetration of the bullet into the
Answer» As the bullet with velocity 150 m/s COMES to REST in 0.03 seconds, its acceleration a = v-u / t = 0 - 150 / 0.03 = -5000 m/s^2 Therefore, distance TRAVELLED in this time S = ut + 1/2at^2 = 1500.03 - (1/25000*0.0009) = 4.5 - 2.25 = 2.25 m The distance of penetration of the bullet into the block is 2.25 m.

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A bullet of mass 10g travelling horizontally with a velocity of 150 m/s strikes a stationary wooden block and comes to rest in 0.03 sec. Calculate the distance of penetration of the bullet into the

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