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A bullet of mass `2 gm` is having a charge of `2 muc`. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of `10 m//s`A. `5 kV`B. `50 kV`C. `5 V`D. `50 V` |
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Answer» Correct Answer - B By using `(1)/(2) mv^(2) = QV` Given, `m = 2g = 2 xx 10^(-3) kg, v = 10 m//s` `q = 2muC = 2 xx 10^(-6) C` Substituting the value in relation for `V`, we obtain `V = (2 xx 10^(-3) xx (10)^(2))/(2 xx 2 xx 10^(-6))` `= 50 xx 10^(3) V = 50 kV` |
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