1.

A bullet of mass `2 gm` is having a charge of `2 muc`. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of `10 m//s`A. `5 kV`B. `50 kV`C. `5 V`D. `50 V`

Answer» Correct Answer - B
By using `(1)/(2) mv^(2) = QV`
Given, `m = 2g = 2 xx 10^(-3) kg, v = 10 m//s`
`q = 2muC = 2 xx 10^(-6) C`
Substituting the value in relation for `V`, we obtain
`V = (2 xx 10^(-3) xx (10)^(2))/(2 xx 2 xx 10^(-6))`
`= 50 xx 10^(3) V = 50 kV`


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