A bullet of mass 20 grams moving with a velocity of 300m/s gets embedd

1.	A bullet of mass 20 grams moving with a velocity of 300m/s gets embedded in a freely suspended wooden block of mass 880 gram. What is the velocity acquired by the block
Answer» Hi friends here your answer given DATA :- mass of bullet = 20÷ 1000 = 2× 10-^2 velocity U1 = 300 m/s mass of wooden block = 880÷1000 = 0.88 kg now law of momentum conservation momentum before collision = momentum after collision mu1 + mu2 = mv1 +mv2 0.02 × 300 + 0 = v ( m1 + m2) 6 = v ( 0.02 + 0.88) 6 = v × 0.9 v = 60 /9 v = 6.66 m/s

A bullet of mass 20 grams moving with a velocity of 300m/s gets embedded in a freely suspended wooden block of mass 880 gram. What is the velocity acquired by the block

Answer»

Hi friends here your answer

given DATA :-

mass of bullet = 20÷ 1000

= 2× 10-^2

velocity U1 = 300 m/s

mass of wooden block = 880÷1000

= 0.88 kg

now

law of momentum conservation

momentum before collision = momentum after collision

mu1 + mu2 = mv1 +mv2

0.02 × 300 + 0 = v ( m1 + m2)

6 = v ( 0.02 + 0.88)

6 = v × 0.9

v = 60 /9

v = 6.66 m/s

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A bullet of mass 20 grams moving with a velocity of 300m/s gets embedded in a freely suspended wooden block of mass 880 gram. What is the velocity acquired by the block ​

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A bullet of mass 20 grams moving with a velocity of 300m/s gets embedded in a freely suspended wooden block of mass 880 gram. What is the velocity acquired by the block