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A bullet of mass `50g` moving with a speed of `500 ms^(-1)` is brought to rest in `0.01s` Find the impulse and the average force . |
Answer» Correct Answer - `-25 N_s, - 2500 N` . Here, `m = 50 g = 0.05 kg, u =500 m//s` `upsilon = 0, t = 0.01 s` Impulse = change in momentum `m (upsilon - m) = 0.05 (0-500)= - 25 Ns` As Impulse ` = Fxxt` `:. - 25 = F xx 0.01, F = -(25)/(0.01) = - 2500 N` . |
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