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A bullet shot with a velocity of 16m/s penetrates a treetrunk and come to rest in 0.4m. In what time does itcomes to rest? |
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Answer» Initial velocity= u= 16 m/sdistance covered = S= 0.4 mFinal velocity=v= 0 m/s the equation of motion;v²=u²+2aS 0=16²+2 x a x 0.4 a=-16²/0.8 a=-320 m/s As it carries a negative sign it represent retardation. Time taken during the retardation is given by the equation;v=u+at0= 16-320 x t t=16/320 t=1/20 t=0.05 s |
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