1.

A bullet shot with a velocity of 16m/s penetrates a treetrunk and come to rest in 0.4m. In what time does itcomes to rest?

Answer»

Initial velocity= u= 16 m/sdistance covered = S= 0.4 mFinal velocity=v= 0 m/s

the equation of motion;v²=u²+2aS

0=16²+2 x a x 0.4 a=-16²/0.8 a=-320 m/s

As it carries a negative sign it represent retardation.

Time taken during the retardation is given by the equation;v=u+at0= 16-320 x t t=16/320 t=1/20 t=0.05 s



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