A bus covers a distance of 30 km during the first hour of its motion,

1.	A bus covers a distance of 30 km during the first hour of its motion, 40 km during the second hour of its motion and 26 km during the third hour of its motion. Calculate the average speed and velocity.
Answer» Answer: average speed = distance/ time distance = (30 + 40 + 26) KM = 96 km time 3 hr average speed 96 km/3 hr = 32 km/hr average velocity = DISPLACEMENT/ time From the given information, the motion APPEARS in straight line without changing any direction. hence displacement and distance are equal Hence average velocity 32 km/hr

A bus covers a distance of 30 km during the first hour of its motion, 40 km during the second hour of its motion and 26 km during the third hour of its motion. Calculate the average speed and velocity.

Answer»

Answer:

average speed = distance/ time

distance = (30 + 40 + 26) KM = 96 km

time 3 hr

average speed 96 km/3 hr = 32 km/hr

average velocity = DISPLACEMENT/ time

From the given information, the motion APPEARS in straight line

without changing any direction.

hence displacement and distance are equal

Hence average velocity 32 km/hr

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A bus covers a distance of 30 km during the first hour of its motion, 40 km during the second hour of its motion and 26 km during the third hour of its motion. Calculate the average speed and velocity.

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