InterviewSolution
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InterviewSolution
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A bus is travelling at speed of 15m/s. Then it accelerates for 5s at a rate of 10m/s2. Find the final velocity and distance covered by the bus during this process. |
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Answer» - Initial velocity = U = 15 ms-¹Acceleration = a = 10 ms-²Time taken = t = 5sNow, Using first EQUATION of motion we can find the final velocity,V = u + at v = 15 + 10 × 5 v = 65 ms-¹Again,we can solve the distance COVERED by using both second and third equation of motion. So using second equation,S = ut + 1/2 at²S = 15 × 5 + 1/2 × 10 × 5 × 5 S = 75 + 125 S = 200 m Using third equation,v² - u² = 2aS (v-u)(v+u) = 2(10)S [v² - u² = (v-u)(v+u) (65-15)(65+15) = 20S20S = 4000S = 200 m Hence,The final velocity = v = 65 ms-¹Distance covered = S = 200 m |
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