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A bus starts moving with uniform acceleration fromits position of rest. It moves 48 m in 4 s. On apply-ing the brakes, it stops after covering 24 m. Find thedeceleration of the bus. |
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Answer» During first 4 sS = ut + 0.5at²48 m = (0 m/s × 4 s) + (0.5 × a × (4 s)²)48 m = (a × 8s²)a = 6 m/s² Velocity at the end of 4s isv = u + at= 0 m/s + (6 m/s² × 4 s)= 24 m/s Now, for rest of the journeya’ = (v² - u²) / (2S)= (0² - 24²) / (2 × 24)= -12 m/s² ∴ Deceleration of bus is 12 m/s² thank you very much |
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