1.

A calorimeter has mass 100 g andspecific heat 0.1 kcal/ kg °C. Itcontains 250 gm of liquid at 30 °Chaving specific heat of 0.4 kcal/kg°C. If we drop a piece of ice of mass10 g at 0 °C, What will be thetemperature of the mixture?​

Answer»

Answer:

20.83°C

Explanation:

Solution

Let the final temperature attained be T. then,

heat given by CALORIMETER + heat given by liquid

= heat absorbed by ice

⇒Mc SC(30−T)+MLSL (30−T)

=MI[Lfusion+SW(T−0)]

⇒(100)(0.1)(30−T)+(250)(0.4)(30−T)

=10[80+1(T−0)]

⇒(110)(30−T)=10[80+T]

⇒330−11T=80+T

⇒T= 12(330−80)

=20.83° C



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