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A calorimeter has mass 100 g andspecific heat 0.1 kcal/ kg °C. Itcontains 250 gm of liquid at 30 °Chaving specific heat of 0.4 kcal/kg°C. If we drop a piece of ice of mass10 g at 0 °C, What will be thetemperature of the mixture? |
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Answer» Answer: 20.83°C Explanation: Solution Let the final temperature attained be T. then, heat given by CALORIMETER + heat given by liquid = heat absorbed by ice ⇒Mc SC(30−T)+MLSL (30−T) =MI[Lfusion+SW(T−0)] ⇒(100)(0.1)(30−T)+(250)(0.4)(30−T) =10[80+1(T−0)] ⇒(110)(30−T)=10[80+T] ⇒330−11T=80+T ⇒T= 12(330−80) =20.83° C |
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