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| 1. | A can do a job in 16 days and B can do the same job in 12 days. With the help of C. they can finish the job in 6 days only. Then, C alone can finish it in34 days22 days36 days48 days | 
| Answer» we know that, Number of hours A required to do piece of work = 16 days Number of hour B required to do piece of work = 12 days Let us consider number of days C required to do piece of work = x days Number of hours A,B and C together required to do piece of work = 6 days ∴ We can calculate, work done by A in 1 day = 1/16 Work done by B in 1 day = 1/12 Work done by C in 1 day = 1/x Work done by A, B and C together in a 1 day = 1/6 Now, work done by A,B and C together in 1 day = 1/16 + 1/12 +1/x = 7/48 + 1/x 7/48 + 1/x = 1/6 (7x+48)/48x = 1/6 42x + 288 = 48x 6x = 288 x = 288/6 = 48 ∴ C can do the work in 48 days. | |