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| 1. | A can do a piece of work in 24 hours while B alone can do it in 16 hours. If A, B and C working together can finish it in 8 hours, in how many hours can C alone finish the work? | 
| Answer» we know that, Number of hours A required to do piece of work = 24 hours Number of hour B required to do piece of work = 16 hours Let us consider number of hours C required to do piece of work = x hours Number of hours A,B and C together required to do piece of work = 8 hours ∴ We can calculate, work done by A in 1 hour = 1/24 Work done by B in 1 hour = 1/16 Work done by C in 1 hour = 1/x Work done by A, B and C together in a one hour = 1/8 Now, work done by A,B and C together in 1 hour= 1/24 + 1/16 +1/x = 5/48 + 1/x 5/48 + 1/x = 1/8 (5x+48)/48x = 1/8 40x + 384 = 48x 8x = 384 x = 384/8 = 48 ∴ C can do the work in 48 hours. | |