1.

A works twice as fast as B. If both of them can together finish a piece of work in 12 days. Then B alone can do it in24 days27 days36 days48 days

Answer»

we know that,

Work done by A in 1 day = 2x

Let us consider work done by B in 1 day = x

Number of days A and B together required to complete a piece of work = 12 days

Now, work done by both A and B together in 1 day= 1/12

∴ 2x + x = 1/12

3x = 1/12

x = 1/36

∴ B can do work in 36 days



Discussion

No Comment Found

Related InterviewSolutions