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A can do a piece of work in 30 days. He worked for 6 days and B finished the remaining work in 48 days. B alone can do the whole work in how many days? Options: 1) 602) 55 3) 75 4) 70 |
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Answer» Explanation: Total time required by A to COMPLETE the work= 30 days Remaining work 24 days of work of A is completed by A and B both in 9 days A×24 =(A+B)×9 A/9 = (A+B)/24 That means B/15 ( the values in denominators are their per day speeds with which they work) So to total work = A×6 +(A+B)×9 =9×6 + 24*9 = 270 units Time taken by B= 270/15 = 18 days if this helps you mark as BRAINLEST answer please |
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