A Can Do A Piece Of Work In 80 Days. He Works At It For 10 Days And T

1.	A Can Do A Piece Of Work In 80 Days. He Works At It For 10 Days And Then B Alone Finishes The Work In 42 Days. The Two Together Could Complete The Work In?
Answer» A’s 10 DAYS WORK = (10 x 1/80) = 1/8 Remaining work = (1 -1/8) = 7/8 Therefore 7/8 work is done by A in 42 days. Whole work will be done by A in (42 x 8/7)i.e.., 48 days Therefore, (A+ B)’s 1 DAY work = (1/80 + 1/48) = 8/240 = 1/30. A and B together can finish it in 30days. A’s 10 days work = (10 x 1/80) = 1/8 Remaining work = (1 -1/8) = 7/8 Therefore 7/8 work is done by A in 42 days. Whole work will be done by A in (42 x 8/7)i.e.., 48 days Therefore, (A+ B)’s 1 day work = (1/80 + 1/48) = 8/240 = 1/30. A and B together can finish it in 30days.

A Can Do A Piece Of Work In 80 Days. He Works At It For 10 Days And Then B Alone Finishes The Work In 42 Days. The Two Together Could Complete The Work In?

Answer»

A’s 10 DAYS WORK = (10 x 1/80) = 1/8

Remaining work = (1 -1/8) = 7/8

Therefore 7/8 work is done by A in 42 days.

Whole work will be done by A in (42 x 8/7)i.e.., 48 days

Therefore, (A+ B)’s 1 DAY work = (1/80 + 1/48) = 8/240 = 1/30.

A and B together can finish it in 30days.

A’s 10 days work = (10 x 1/80) = 1/8

Remaining work = (1 -1/8) = 7/8

Therefore 7/8 work is done by A in 42 days.

Whole work will be done by A in (42 x 8/7)i.e.., 48 days

Therefore, (A+ B)’s 1 day work = (1/80 + 1/48) = 8/240 = 1/30.

A and B together can finish it in 30days.

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