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Two Pipes A And B Can Fill A Tank In 15 Min And 20 Min Respectively. Both The Pipes Are Opened Together But After 4 Min, Pipe A Is Turned Off. What Is The Total Time Required To Fill The Tank? |
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Answer» Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15 REMAINING part = 1 - 7/15 = 8/15 Part filled by B in 1 minute = 1/20 1/20 : 8/15 :: 1 ; X x = 8/15 * 1 * 20 = 10 2/3 min = 10 min 40 SEC. The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec. Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15 Remaining part = 1 - 7/15 = 8/15 Part filled by B in 1 minute = 1/20 1/20 : 8/15 :: 1 ; x x = 8/15 * 1 * 20 = 10 2/3 min = 10 min 40 sec. The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec. |
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