InterviewSolution
Saved Bookmarks
| 1. |
Two Pipes A And B Together Can Fill A Cistern In 4 Hours. Had They Been Opened Separately, Then B Would Have Taken 6 Hours More Than A To Fill Cistern. How Much Time Will Be Taken By A To Fill The Cistern Separately? |
|
Answer» Let the CISTERN be filled by PIPE A alone in x hours. Then, pipe B will FILL it in (x + 6) hours. 1/x + 1/(x + 6) = 1/4 x2 - 2x - 24 = 0 (x - 6)(x + 4) = 0 => x = 6. Let the cistern be filled by pipe A alone in x hours. Then, pipe B will fill it in (x + 6) hours. 1/x + 1/(x + 6) = 1/4 x2 - 2x - 24 = 0 (x - 6)(x + 4) = 0 => x = 6. |
|