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A Can Finish A Work In 18 Days B Can Do The Same Work In 15 Days. B Worked For 10 Days And Left The Job. In How Many Days, A Alone Can Finish The Remaining Work? |
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Answer» B's 10 DAY's work = 1/15 * 10 = 2/3 REMAINING work = (1 - 2/3) = 1/3 Now, 1/18 work is done by A in 1 day. 1/3 work is done by A in (18 * 1/3) = 6 days. B's 10 day's work = 1/15 * 10 = 2/3 Remaining work = (1 - 2/3) = 1/3 Now, 1/18 work is done by A in 1 day. 1/3 work is done by A in (18 * 1/3) = 6 days. |
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