InterviewSolution
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InterviewSolution
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A cannot engine has efficiency `(1)/(6)`. If temperature of sink is decreased by `62^(@)C` then its efficiency becomes `(1)/(3)` then the temperature of source and sink:A. `37^(@)C`B. `62^(@)C`C. `99^(@)C`D. `12^(@)C` |
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Answer» Correct Answer - C Here, `eta_(1)= 1/6, eta_(2)= 2xx1/6` From `eta_(1)= 1-(T_(1))/(T_(1))` `1/6= 1-(T_(2))/(T_(1)), (T_(2))/(T_(1))= 5/6 or T_(2)= (5T_(1))/6` Again, `eta_(2)= 1-((T_(2)-62))/(T_(1))` `((T_(2)-62))/(T_(1))= 1-1/3= 2/3` `3T_(2)-186= 2T_(1)` `3xx5/6T_(1)-186= 2T_(1)` `0.5T_(1)= 186` `T_(1)=372K= 372-273= 99^(@)C` |
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